Optimal. Leaf size=188 \[ \frac {2^{-m-1} \left (2 m^4-440 m^3+29050 m^2-639760 m+3528363\right ) (2 x+1)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (2 x+1))}{1215 (1-m)}-\frac {(3 x+2)^{m+1} \left (-2 m^3-24 \left (m^2-154 m+4359\right ) x+426 m^2-25441 m+386850\right ) (2 x+1)^{1-m}}{1215}-\frac {2}{15} (5-4 x)^3 (3 x+2)^{m+1} (2 x+1)^{1-m}-\frac {1}{45} (88-m) (5-4 x)^2 (3 x+2)^{m+1} (2 x+1)^{1-m} \]
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Rubi [A] time = 0.23, antiderivative size = 188, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {100, 153, 147, 69} \[ \frac {2^{-m-1} \left (2 m^4-440 m^3+29050 m^2-639760 m+3528363\right ) (2 x+1)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (2 x+1))}{1215 (1-m)}-\frac {(3 x+2)^{m+1} \left (-24 \left (m^2-154 m+4359\right ) x-2 m^3+426 m^2-25441 m+386850\right ) (2 x+1)^{1-m}}{1215}-\frac {2}{15} (5-4 x)^3 (3 x+2)^{m+1} (2 x+1)^{1-m}-\frac {1}{45} (88-m) (5-4 x)^2 (3 x+2)^{m+1} (2 x+1)^{1-m} \]
Antiderivative was successfully verified.
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Rule 69
Rule 100
Rule 147
Rule 153
Rubi steps
\begin {align*} \int (5-4 x)^4 (1+2 x)^{-m} (2+3 x)^m \, dx &=-\frac {2}{15} (5-4 x)^3 (1+2 x)^{1-m} (2+3 x)^{1+m}+\frac {1}{30} \int (5-4 x)^2 (1+2 x)^{-m} (2+3 x)^m (2 (397-10 m)-16 (88-m) x) \, dx\\ &=-\frac {1}{45} (88-m) (5-4 x)^2 (1+2 x)^{1-m} (2+3 x)^{1+m}-\frac {2}{15} (5-4 x)^3 (1+2 x)^{1-m} (2+3 x)^{1+m}+\frac {1}{720} \int (5-4 x) (1+2 x)^{-m} (2+3 x)^m \left (16 \left (7627-609 m+5 m^2\right )-64 \left (4359-154 m+m^2\right ) x\right ) \, dx\\ &=-\frac {1}{45} (88-m) (5-4 x)^2 (1+2 x)^{1-m} (2+3 x)^{1+m}-\frac {2}{15} (5-4 x)^3 (1+2 x)^{1-m} (2+3 x)^{1+m}-\frac {(1+2 x)^{1-m} (2+3 x)^{1+m} \left (386850-25441 m+426 m^2-2 m^3-24 \left (4359-154 m+m^2\right ) x\right )}{1215}+\frac {\left (3528363-639760 m+29050 m^2-440 m^3+2 m^4\right ) \int (1+2 x)^{-m} (2+3 x)^m \, dx}{1215}\\ &=-\frac {1}{45} (88-m) (5-4 x)^2 (1+2 x)^{1-m} (2+3 x)^{1+m}-\frac {2}{15} (5-4 x)^3 (1+2 x)^{1-m} (2+3 x)^{1+m}-\frac {(1+2 x)^{1-m} (2+3 x)^{1+m} \left (386850-25441 m+426 m^2-2 m^3-24 \left (4359-154 m+m^2\right ) x\right )}{1215}+\frac {2^{-1-m} \left (3528363-639760 m+29050 m^2-440 m^3+2 m^4\right ) (1+2 x)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (1+2 x))}{1215 (1-m)}\\ \end {align*}
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Mathematica [A] time = 0.41, size = 227, normalized size = 1.21 \[ \frac {(2 x+1)^{1-m} \left (483 \left (2^{-m} \left (-2 m^2+132 m-1453\right ) \, _2F_1(1-m,-m;2-m;-6 x-3)+4 (m-1) (m+12 x-59) (3 x+2)^{m+1}\right )-(88-m) \left (2^{2-m} (m-66) \, _2F_1(-m-2,1-m;2-m;-6 x-3)+23\ 2^{1-m} (111-2 m) \, _2F_1(-m-1,1-m;2-m;-6 x-3)+529\ 2^{-m} (m-45) \, _2F_1(1-m,-m;2-m;-6 x-3)-18 (m-1) (5-4 x)^2 (3 x+2)^{m+1}\right )-108 (m-1) (4 x-5)^3 (3 x+2)^{m+1}\right )}{810 (1-m)} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.15, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (256 \, x^{4} - 1280 \, x^{3} + 2400 \, x^{2} - 2000 \, x + 625\right )} {\left (3 \, x + 2\right )}^{m}}{{\left (2 \, x + 1\right )}^{m}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{m} {\left (4 \, x - 5\right )}^{4}}{{\left (2 \, x + 1\right )}^{m}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.24, size = 0, normalized size = 0.00 \[ \int \left (-4 x +5\right )^{4} \left (2 x +1\right )^{-m} \left (3 x +2\right )^{m}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{m} {\left (4 \, x - 5\right )}^{4}}{{\left (2 \, x + 1\right )}^{m}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (3\,x+2\right )}^m\,{\left (4\,x-5\right )}^4}{{\left (2\,x+1\right )}^m} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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